The two normal modes of a coupled pair at kc/k = 0.1
At its defaults it draws the two normal modes of a coupled pair at kc/k = 0.1. Two equal masses, each held to a wall by a spring of stiffness k and to each other by a coupling spring of 0.1k. Above: the in-phase mode, in which both masses move the same way by the same distance, the coupling spring never changes length, and the frequency is therefore 1.0000√(k/m) — the coupling does not appear in it at all. Below: the out-of-phase mode, in which the coupling spring changes length by twice the displacement, so each mass feels k + 2kc and the frequency rises to 1.0954√(k/m), a ratio of 1.0954. Both displacement patterns are the eigenvectors of the pair's stiffness matrix, obtained from its trace and determinant and checked against those two square roots. The red arrows are the force each mass is pulled back by, computed as −Kx: 1.00kA in the first mode against 1.20kA in the second, a factor of 1.20, which is the square of the frequency ratio because ω² is a stiffness over a mass. Any motion of the pair whatsoever is a sum of these two and nothing else.
normal-modes is one function in lib/figures/mechanics.js —
motion, force, energy and rotation. Everything below came out
of it during this build, at parameters taken from the essays rather than invented for this
page. A figure here is the figure a reader meets in an essay, and if the generator changes,
this page changes with it.
At its defaults
Drawn even though every essay passes options, because a default nothing exercises is a trap for the next essay to call this with none — which has happened here twice.
Two equal masses, each held to a wall by a spring of stiffness k and to each other by a coupling spring of 0.1k. Above: the in-phase mode, in which both masses move the same way by the same distance, the coupling spring never changes length, and the frequency is therefore 1.0000√(k/m) — the coupling does not appear in it at all. Below: the out-of-phase mode, in which the coupling spring changes length by twice the displacement, so each mass feels k + 2kc and the frequency rises to 1.0954√(k/m), a ratio of 1.0954. Both displacement patterns are the eigenvectors of the pair's stiffness matrix, obtained from its trace and determinant and checked against those two square roots. The red arrows are the force each mass is pulled back by, computed as −Kx: 1.00kA in the first mode against 1.20kA in the second, a factor of 1.20, which is the square of the frequency ratio because ω² is a stiffness over a mass. Any motion of the pair whatsoever is a sum of these two and nothing else.
The condition three modes never quite satisfy
The options are the ones The condition three modes never meet passes. A branch drawn at its own defaults instead would be a picture no essay asked for and no assertion has been run against.
By how much three modes of a thirty-two mass chain fail to be in resonance — the sum of two mode frequencies minus the frequency of their sum, on a logarithmic scale, against the second of the two modes for four choices of the first. The leading nonlinear term couples modes in threes and the exchange accumulates only where this quantity is zero. It never is: the chain's dispersion is a sine, a sine is concave, and the sum of two of its values always exceeds the value at their sum. The smallest mismatch anywhere on the chain is at the two lowest modes and equals 2.156e-4 — which the scan finds and which is the cube of pi over four times the cube of one more than the mode count, checked here on chains from eight masses to two hundred and fifty-six. That closed form is the whole of why this is a finite-chain problem: the mismatch falls as the cube of the length, so a long enough chain is arbitrarily close to resonant and the continuum limit is exactly resonant, which is where the solitary waves come from.
What a mismatch turns a transfer into
The options are the ones The condition three modes never meet passes. A branch drawn at its own defaults instead would be a picture no essay asked for and no assertion has been run against.
The fraction of the energy that has crossed from one oscillator to a second one coupled to it, against time, for four amounts of frequency mismatch between them — in units where the coupling is one. With the two exactly in tune, all of the energy crosses and comes back. With them detuned, only part of it ever crosses, and the fraction is 1/(1 + (Δ/2V)²): 100.0 per cent at a detuning of 0, 80.0 per cent at a detuning of 1, 30.8 per cent at a detuning of 3, 5.9 per cent at a detuning of 8 — measured by integrating the two coupled equations and checked against the closed form to three parts in a thousand. This is the whole mechanism the previous figure implies. A mismatch does not prevent two modes from exchanging energy; it caps how much of it ever crosses and makes the exchange periodic, so nothing accumulates. The exchange also gets faster as the detuning grows, which is the counterintuitive half: the beat frequency is the root of the squared detuning plus four times the squared coupling, so a badly matched pair swaps a little energy quickly and a well matched pair swaps all of it slowly.
A longer chain shares more, and the reason is arithmetic
The options are the ones The condition three modes never meet passes. A branch drawn at its own defaults instead would be a picture no essay asked for and no assertion has been run against.
How spread the energy is across the modes after four hundred periods of the longest mode, against the least three-wave mismatch that chain has, for six chains from sixteen masses to ninety-six — logarithmic in the mismatch. Two things are held fixed and the work is in holding them: the energy per mass, chosen for each chain by bisection so that a longer chain is not simply given more energy, and the run length in units of each chain's own longest period, since a longer chain is slower. What is left varying is the mismatch, which falls as the cube of the length. The spread rises from 0.651 at 16 masses to 0.900 at 96, and the line through the points slopes the way the mechanism requires. This is a prediction the empirical curve could not have made: it says nothing about chain length, and the observation that a long chain thermalises more readily at the same energy density follows from the resonance condition and from nothing else.
The energy density at which the chain gives in
The options are the ones The condition three modes never meet passes. A branch drawn at its own defaults instead would be a picture no essay asked for and no assertion has been run against.
How spread the energy is at the end of a run of 160 periods, against the energy per mass the chain was given, on a logarithmic scale. At a density of 2.3e-3 it reaches 0.33; At a density of 9.3e-3 it reaches 0.40; At a density of 2.1e-2 it reaches 0.45; At a density of 4.7e-2 it reaches 0.54; At a density of 9.9e-2 it reaches 0.66; At a density of 1.9e-1 it reaches 0.75; At a density of 3.4e-1 it reaches 0.87. The curve is flat and low at small densities and climbs steeply over about a decade. What that means is that the failure of equipartition is not permanent and not universal: it is a statement about a timescale. Below the threshold the chain would eventually share its energy out, on a time longer than the run — and the time grows so fast as the density falls that it passes any patience. Above it, the sharing happens while anyone is watching. The original calculation ran for a few thousand periods at a density well below this curve's knee, which is why it found a recurrence rather than a thermal chain. Running the same problem for long enough, or hitting it harder, gives the answer equipartition predicts.
One rate law, found by looking for it
The options are the ones The condition three modes never meet passes. A branch drawn at its own defaults instead would be a picture no essay asked for and no assertion has been run against.
How spread the energy is across the chain's modes — the entropy of its distribution, one being equipartition — against time multiplied by a power of the amplitude, for four runs of a thirty-two mass chain differing only in how hard it was struck. The exponent is not assumed: it is scanned for, and the value that lines the four curves up is 1.75, which reduces the spread between them by a factor of 3 against plotting them against time alone. That a single power works at all is the result — it says the four runs are the same process at different speeds rather than four different ones. What the figure cannot reach is the regime the original calculation was in. These amplitudes are above the knee where the sharing becomes fast enough to watch; below it the rate is predicted to fall as a much higher power of the nonlinearity, and no run of a length anybody will wait for gets near it. The exponent here belongs to this range and is not the exponent of the weakly nonlinear theory.
What checks it
physicscheck asserts something about normal-modes that
could fail — it draws it and measures the result against a value reached some other
way.
Across the library: 100 interrogated, 2 exercised only, 1 untouched, of 103. Read out of the gate's source by the gate's own two patterns — and the gate's last claim fails the build if that read disagrees with what it was handed while running.
Where it is called
Changing this generator changes every figure on this list. That is what makes the list worth publishing rather than keeping in a check script.
The condition three modes never meet
Whether two modes of a chain can hand energy to a third is arithmetic on the dispersion relation, and for a chain of masses the answer is never: a sine is concave, so the sum of two frequencies always exceeds the frequency of their sum. The smallest shortfall anywhere on a chain of N masses is π³/4(N+1)³ — never zero, and never far from it — and a shortfall turns a transfer into a beat.
ThermodynamicsThe energy that refuses to be shared
Put all the energy of a chain of masses into its longest mode and add a few per cent of nonlinearity, and equipartition says it should spread out among all thirty-two modes and stay there. It does not. It leaks into three or four neighbours and then comes back — almost exactly — and goes on doing so, and the calculation that found this was expected to be a demonstration that it would not happen.
WavesThe frequency a lattice cannot carry
A continuous string carries every note. A row of masses joined by springs does not: there is a highest frequency, set by nothing but the time one mass takes to be pushed back by its neighbours, and above it a disturbance does not travel at all.
WavesThe mass that makes another stand still
Bolt a small mass on a spring to a machine that is shaking itself apart, tune it to the frequency that is doing the damage, and the machine stops moving. Not moves less — stops, exactly, at that one frequency. The price is two new resonances either side of it, and the whole device is a bet that the drive stays where it was put.
MechanicsThe two pendulums that will not stop swapping
Coupled oscillators joined by a weak spring appear to hand energy back and forth. Nothing is handed anywhere: the system has only a pair of motions that keep their shape, at √(k/m) and √((k+2kc)/m), and the apparent traffic is the beat between them — 51 swings from one handover to the next at a coupling of one part in fifty. Extend the same arithmetic to N masses and it produces a dispersion relation with a hard ceiling, near 7 THz in copper.